You have a 12-gallon bucket, an 8-gallon bucket and a 5-gallon bucket. The 12-gallon bucket is full of water and the other two are empty. Without using any additional water how can you divide the twelve gallons of water equally so that two of the three buckets have exactly 6 gallons of water in them?
I and my nephew spent a good deal of time trying to solve it and ultimately gave up.
I remembered then that I have seen a programmatic solution to a similar puzzle being worked out in the "Functional Programming Principles in Scala" Coursera course by Martin Odersky.
This is the gist to the solution completely copied from the course:
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package bucket | |
case class Pouring(capacity: Vector[Int], initialState: Vector[Int]){ | |
type State = Vector[Int] | |
trait Move { | |
def change(state: State): State | |
} | |
case class Pour(from: Int, to: Int) extends Move { | |
def change(state: State) = { | |
val amount = state(from) min (capacity(to) - state(to)) | |
state updated (from, state(from) - amount) updated (to, state(to) + amount) | |
} | |
} | |
class Path(history: List[Move], val endState: State) { | |
def extend(move: Move) = new Path(move :: history, move change endState) | |
override def toString = (history.reverse mkString " ") + "-->" + endState | |
} | |
val glasses = 0 until capacity.length | |
val moves = for { | |
from <- glasses | |
to <- glasses | |
if (from != to) | |
} yield Pour(from, to) | |
val initialPath = new Path(Nil, initialState ) | |
def from(paths: Set[Path], explored: Set[State]): Stream[Set[Path]] = { | |
if (paths.isEmpty) Stream.empty | |
else { | |
val more = for { | |
path <- paths | |
next <- moves map path.extend | |
if !(explored contains next.endState) | |
} yield next | |
paths #:: from(more, explored ++ (more map (_.endState))) | |
} | |
} | |
val pathSets = from(Set(initialPath), Set(initialState)) | |
def solution(target: State): Stream[Path] = { | |
for { | |
pathSet <- pathSets | |
path <- pathSet | |
if (path.endState == target) | |
} yield path | |
} | |
} |
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package bucket | |
import org.scalatest.FunSuite | |
import org.junit.runner.RunWith | |
import org.scalatest.junit.JUnitRunner | |
@RunWith(classOf[JUnitRunner]) | |
class PouringTest extends FunSuite { | |
test("Solution to the 12-gallon, 8-gallon, 5-gallon problem") { | |
val p = Pouring(Vector(12, 8, 5), Vector(12, 0, 0)) | |
println(p.solution(Vector(6, 6, 0))) | |
} | |
} |
and running this program spits out the following 7 step solution! (index 0 is the 12-gallon bucket, 1 is the 8-gallon bucket and 2 is the 5-gallon bucket)
1 2 3 4 5 6 7 | Pour( 0 , 1 ) Pour( 1 , 2 ) Pour( 2 , 0 ) Pour( 1 , 2 ) Pour( 0 , 1 ) Pour( 1 , 2 ) Pour( 2 , 0 ) |
If you are interested in learning more about the code behind this solution, the best way is to follow the week 7 of the Coursera course that I have linked above, Martin Odersky does a fantastic job of seemingly coming up with a solution on the fly!.
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